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Page history last edited by alfredo 14 years, 3 months ago




By: Noora, Lida, Ahsan, Andrea L., Matteo


You receive a sample of a salt formed by an "s-block" metal and an halogen. The amount of this sample contains as many halogen ions as there are in 1,00 grams of sodium chloride. You have to recognize the metal and the halogen in that salt.


Vi viene assegnato un campione di sale formato da un metallo del "blocco s" e da un alogeno. La quantità di questo campione contene tanti ioni alogenuro quanti ve ne sono in 1,00 g di cloruro di sodio. Dovete riconoscere il metallo e l'alogeno nel sale.


Saat suolanäytteen, joka koostuu alkali- tai maa-alkaliryhmän metallista (=s-ryhmä) ja halogeenista. Näyte sisältää yhtä monta halogeeni-ionia kuin 1,00 grammassa natriumkloridia (NaCl) on kloridi-ioneita. Tehtävänä on tunnistaa, mistä metalli- ja halogeeni-ioneista suola koostuu.


1. Useful knowledge (reference data, concepts and principles)


1.1 Colours of alkali metals to the bunsen flame:

Lithium  Sodium  Potassium  Calcium  Strontium  Barium 
Deep Purple  Yellow-Orange  Lilac 





1.2 Atomic relative mass of sodium and chlorine: Na= 22,99 Cl= 35,33

1.3 Formula Weight of NaCl: 58,44

1.4 Formula of a salt formed by Me+ and X- ions: MeX 

1.5 Formula of a salt formed by Me2+ and X- ions:MeX2


2. Main idea

We recognize the metal with the flame test and the halogen through calculation based on the weight of the salt  .


 3. Planning

1.weigh the bowl with the salt

2.weigh the empty container

3.kindle the flame

4.we clean nickel wire

5.bathe the wire in the HCl

6 bathe the wire in the wet bowl of salt 

observe the flame test color since



4.  Report


Italian  19-03-2010

Ahsan, Matteo, Andrea L, 

Finnish (date of the experiment)

plastic box with salt =3,97 g

empty box =1.89 g

salt = 2,08 g

flame test= green-yellow 


empty box=13.5g



flame test= green, yellow






5. Elaboration and Interpretation


Italian   Finnish      

salt mass = 3.97-1.89 = 2.08 g

Metal-ion = barium

barium atomic mass = 137.327 amu

Ba ions are Ba2+.

our salt formula should be BaCl2

number of halide ions = number of chloride ions in 1 g of NaCl = number of NaCl couples in 1 g of NaCl = 1 g..................


Salt = 2,2 g

metal-ion= barium

Ba= 137.3
1g  :58.44 = 0.0171
0.017 : 2 = 0.0085
0.0085 x 137.3 = 1.16705
2.2 - 1.16705 = 1.03295
1.03295 : 0.0171 = 60.4 > Br

Common conclusions





Questions & Answers


1. Why are atoms emitting light at the flame?

1. Perché gli atomi emettono luce alla fiamma?

Because the atoms are more excitable.

Ripsosta 1.


2. How did you recognize the metal element in the salt?

 can be recognized by their color emitted by the flame 


3. What measure permitted you to deduce which halogen was in the salt?

3. Quale misura vi ha permesso di dedurre l'alogeno contenuto nel vostro sale?

Answer 3

Risposta 3


4. Does your salt contain more cations or anions?

4. Il vostro sale contiene più cationi o più anioni?

Answer 4

Risposta 4 


5. Does your salt contain more mass as halide ions or as metal ions or the same?

5. Il vostro sale contiene una massa maggiore di ioni alogenuroo, di ioni del metallo o la stessa?

Answer 5

Risposta 5


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